Garmaine Staff asked 2 years ago

I want to send a POST request to a rest endpoint. the rest endpoint documentation says:

Create a node and add it as a primary child of node nodeId.

This endpoint supports both JSON and multipart/form-data (file upload).

Using multipart/form-data

Use the filedata field to represent the content to upload, for example, the following curl command will create a node with the contents of test.txt in the test user's home folder.

curl -utest:test -X POST host:port/alfresco/api/-default-/public/alfresco/versions/1/nodes/-my-/children -F filedata=@test.txt

You can use the name field to give an alternative name for the new file.

You can use the nodeType field to create a specific type. The default is cm:content

I managed to send a correct request to this endpoint by the following code:

@Override
public ResponseEntity<byte[]> postNode(String nodeId, byte[] content) {
  MultiValueMap<String, Object> bodyMap = new LinkedMultiValueMap<>();
ByteArrayResource contentsAsResource = new ByteArrayResource(content) {
    @Override
    public String getFilename() {
        return "name22222";
    }
};

  bodyMap.add("filedata", contentsAsResource);

  ///bodyMap.add("filedata", content);// why this does not work??!

  HttpHeaders headers = new HttpHeaders();
  headers.setContentType(MediaType.MULTIPART_FORM_DATA);
  HttpEntity<MultiValueMap<String, Object>> requestEntity = new HttpEntity<>(bodyMap, headers);
        return restTemplate.exchange("/nodes/{nodeId}/children", HttpMethod.POST, requestEntity, byte[].class, nodeId);
}

but I have two questions:

1 – why the commented line does not work?

2 – the docs says :

You can use the name field to give an alternative name for the new file.

I did not use a "name" field, but the server saved my files with the correct name(="name22222"), why?(I thought multipart/form-data is a kind of a simple name-value, if this is correct then I have a field named "filedata" and its value is my byte array content, so how the file name is send?). and how can I specify the file name with a field?

update : i think i found my answers. i just need to read about multipart/form-data!